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...произведем, тем нам будет лучше. регулировать, сколько продадим одной группе, сколько другой, мы не можем, поэтому просто произведем по максимуму 60 = 120 / (P - 1) + 90 / (P - 2)
упростила, не знаю, обоснованно ли=) P1 = 120 / Q1 + 1 P2 = 90 / Q2 + 2 TR (общая) = 210 + 2Q(2) + Q(1) чем больше произведем, тем нам будет лучше. регулировать, сколько продадим одной группе...
iloveeconomics.ru/zadachi/z682
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for {p1, p2, p4, p5, r2} is saturated for p. c∆List({1}:q ∧ {1,2,4}:p ∧ {2}:q ) = , for {p5, q 1, q 2, q 3} is saturated for q . Recall that, as established in [6], a ∆-tree will always be interpreted as a conjunctive signed formula and arbitrary signed formulas are represented by means.
sevein.matap.uma.es/~aciego/TR/agv-ib02.pdf
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P3 P2 P1 P0 P < qout p > qout SN54AS885 . . .
P2 P1 NC – No internal connection The latch is transparent when P latch-enable (PLE) input is high; the P-input port is latched when PLE is low. This provides the designer with temporary storage for the P-data word.
www.ti.com/lit/ds/symlink/sn74as885.pdf
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Similarity Search in Theory Search space: object domain U, distance function d Input: database S = {p1 , . . . , pn } ⊆ U Query: q ∈ U Task: nd argminpi d(pi , q) p4 p3 p2 p5 q p1 p6 Data Models: General metric space: triangle inequality + oracle access k -dimensional Euclidean space with Euclidean, Manhattan, Lp or angle metric Strings with.
yury.name/talks/lifshits-google-hand.pdf
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45-th Bulgarian Mathematical Olympiad 1996 Fourth Round First Day 1. Find all prime numbers p and q such that (5 p − 2 p)(5q − 2q) is an integer. pq 2. Find the side length of the smallest equilateral triangle in which three disks with radii 2, 3, 4 and with disjoint interior points can be placed.
www.imocompendium.com/othercomp/Bul/BulMO496.pdf
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www.facebook.com/fukriyan
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For notational convenience we call r = p1 , s = p2 , t = p3 . We organized our search by the number of nonzero functions in the set of seven functions k, l, p1 , p2 , p5 , q, u. The same map was used on all planes of the CAC-cube. 2.3 Invariances Lattice maps are in general invariant under rational linear (Moebius) transformations with constant coecients.
www.atlantis-press.com/php/download_paper.php?id=409
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Term 2: XI X4 (these are both not present in the second path X2 X5) Z(X1 X4) = X1’ + X1 X4’ X2 X5 (X1’ + X1 X4’) P2 P5 (Q1 + P1 Q4).
www.unf.edu/~sahuja/cis6302/releval.doc
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Mq , SONL ≤ p1 + p3 + p5 ≤ 1 +1 < 1. But this would contradict the assumption that q 2 the best possible schedule has a makespan of 1. Hence, Opposite-LPT must schedule both J3 and J4 on M1 .
math.haifa.ac.il/lea/pfh.pdf
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Do there exist 19 distinct positive integers that add up to 1999 and have the same sum of digits? 34. Find all prime numbers p and q such that pq divides the product (5 p − 2 p )(5q − 2q ). 35. Prove that there are innitely many numbers not containing the digit 0 that are divisible by the sum of their digits.
sbelian.files.wordpress.com/2007/11/104-number-theory-problems1.pdf
